2x2-4x-15=0 Two solutions were found : x = (4-√136)/4=1-1/2√ 34 = -1.915 x = (4+√136)/4=1+1/2√ 34 = 3.915 Step by step solution : Step 1 :Equation at the end of step 1 : (2x2 - 4x) - 15 = 0

Take the square root of each side and solve. To make things simple, a general formula can be derived such that for a quadratic equation of the form ax²+bx+c=0 the solutions are x= (-b ±

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2x 2 + x – 15 = 2 ( x - 5 2) ( x + 3) (2) The critical numbers are x - 5 2 = 0 or x + 3 = 0. The critical numbers are x = 5 2 or x = – 3. Divide the number line into three intervals. ( - ∞, - 3), ( - 3

2x2 − x − 15 2 x 2 - x - 15 For a polynomial of the form ax2 +bx+ c a x 2 + b x + c, rewrite the middle term as a sum of two terms whose product is a⋅c = 2⋅−15 = −30 a ⋅ c = 2 ⋅ - 15 = - 30 and

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One plus one is two.